Answer:
-3x+5y=20
Step-by-step explanation:
Standard form is given by ax+by=c
where a , b and c are integers
here we have an equation
\(y=\frac{3}{5}x+4\)
so we first multiply the complete equation by 5 to get rid of the fraction
\(5y=3x+20\)
Now subtract 3x from both side to get the required standard form
\(5y-3x=3x-3x+20\)
-3x+5y=20
