Answer:
45 handshakes
Step-by-step explanation:
If there are n persons and each person shakes every other person hand once then the total number of handshakes are \(\frac{n(n-1)}{2}\)
Now, it has been given that 10 people meet, and each person shakes every other person's hand once.
Therefore, n = 10.
Hence, from the above mentioned formula, we have
Total number of handshakes =
\(\frac{n(n-1)}{2}\)
\(=\frac{10(10-1)}{2}\)
\(=\frac{10\times9}{2}\)
\(=5\times9\)
\(=45\)
Hence, total 45 handshakes were occurred.
