If your body develops a charge of -19 μC (microcoulombs), how many excess electrons has it acquired?
\(1e \ \ \ \ \ \ \rightarrow \ \ \ \ \ \ -1,6*10^{-19}C\\ x \ \ \ \ \ \ \ \rightarrow \ \ \ \ \ \ -19*10^{-6}C\\\\ x = \frac{-19*10^{-6}C*1e}{-1,6*10^{-19}C}=11,875*10^{13}e=1,1875*10^{14}e\)
Answer : The number of electrons it acquired is, \(11.875\times 10^{13}\) electrons
Solution : Given,
Total charge = \(-19\mu C=-19\times 10^{-6}C\) \((1\mu C=10^{-6}C)\)
Charge on one electron = \(-1.60\times 10^{-19}C\)
Formula used :
\(\text{Number of electrons}=\frac{\text{Total charge}}{\text{Charge on one electron}}\)
Now put all the given values in this formula, we get the number of electrons.
\(\text{Number of electrons}=\frac{\text{Total charge}}{\text{Charge on one electron}}=\frac{-19\times 10^{-6}C}{-1.60\times 10^{-19}C}=11.875\times 10^{13}electrons\)
Therefore, the number of electrons it acquired is, \(11.875\times 10^{13}\) electrons.