can anyone simplify 24q2/8q-3
24q^2 / 8q^-3lets break this down...24/8 = 3q^2 / q^-3....when dividing exponents with the same base, keep the base and subtract the exponents. q^2 / q^-3 = q^(2 -(-3) = q^(2 + 3) = q^5put them together and u get : 3q^5
