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A common resistance of carbon resistors is 33 ΩΩ. How many 33 ΩΩ resistor, connected in parallel, are needed to give a total resistance of 5.5 ΩΩ?

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Let n be the required number of 33 ohm resistors.
\(n\times(\frac{1}{33})=\frac{1}{5.}\)
\(n=\frac{33}{5.5}=6\)
The required number of 33 ohm resistors in parallel is 6 resistors.

Answer:

6 resistors.

Step-by-step explanation:

Common resistance of carbon resistors has been given as 3 Ω

When resistors added in parallel connection total resistance is given by the expression

\(\frac{1}{R}\) = \(\frac{1}{R_1}\) + \(\frac{1}{R_2}\)...........\(\frac{1}{R_n}\)

If n resistors have been added then \(\frac{1}{R}\) = \(\frac{n}{r}\)

here r = 3Ω and R = (0.5)Ω

\(\frac{n}{3}\)= \(\frac{1}{0.5}\)

n = \(\frac{3}{0.5}\) =  6 resistors.

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