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bob plays a game at the school fair. he starts with 0 points. he gets 25 throws. he wins 12 points for hitting the target and loses 8 points for each miss. bob ends with a score of 0. how many hits and misses does bob have?

Verified Answer :

You have to find a number that they both multiply into.
12 x 10= 120
8 x 15= 120

caylus

Hello,
Let's
     n the numbers of win throws
  25-n the number of lost

12n+(-8)(25-n)=0
==>12n-200+8n=0
==>20n=200
==>n=10 (win throws)
and 25-10=15 (lost)

Proof: 1012+(-8)15=120-120=0

For  a "11 year old nephew":

multiple of 12 ={0,12,24,36,48,60,72,84,96,108,120,132,144,....}
multiple of 8  =[0,8,16,24,32,40,48,56,64,72,80,88,96,104,112,120,128,136,...}

Commun mutiples are {0,120,240,360...}

0=012-80    and (0-0 not equal to 25)
0=1012-158 and 10+15=25 (get it)

0=2012-830 and (20+8 not equal to 25)

Answer is thus win: 10 and lost 15.
This will be understandable for a kid of 11 years.


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