Answer:
\(y = \frac{82-Vj}{V-61}\)
Step-by-step explanation:
Given the equation: \(V(j+y)= 61y+82\)
Solve for y:
The distributive property says:
\(x \cdot (y+z) = x\cdot y+ x\cdot z\)
Apply the distributive property on a given equation we have;
\(Vj+Vy= 61y+82\)
Subtract 61y from both sides we get;
\(Vj+Vy-61y=82\)
Subtract vj from both sides we get;
\(Vy-61y= 82-Vj\)
or
\(y(V-61)= 82-Vj\)
Divide both sides by v-61 we get;
\(y = \frac{82-Vj}{V-61}\)
Therefore, the value of y is: \(y = \frac{82-Vj}{V-61}\)
