the resistance (r) in a wire increases when the length of the wire (l) increases. write the correct equation for this scenario, and solve for when the length is 1.
Hello,
This is the law of Pouillet.
\(r=\rho* \dfrac{L}{S}\\
if \ L=1\ then\ \boxed{r= \dfrac{\rho}{S} }\)
Answer:
\(r=\frac{\rho}{A}\)
Step-by-step explanation:
Given,
Resistance (r) in a wire increases when the length of the wire (l) increases,
That is, r is proportional to l
\(r\propto l\)
Also, we know that Resistance is inversely proportional to the cross sectional area, A,
That is,
\(r\propto \frac{1}{A}\)
By combining,
\(r\propto \frac{l}{A}\)
\(r=\rho \frac{l}{A}\)
Where, \(\rho\) is the resistivity constant.
Given, l = 1 unit,
Hence, the required formula would be,
\(r=\frac{\rho}{A}\)