what is the mass of a sample of water containing 3.55×1022 molecules of h2o?
6,02×10²³ -------------- 18g
3,55×10²² -------------- x\(x=\frac{3,55*10^{22}*18g}{6,02*10^{23}}=10,61*10^{22-23}g=10,61*10^{-1}g=1,061g\)
Answer: The mass of water sample is 1.062 g
Explanation:
We are given:
Number of molecules of water = \(3.55\times 10^{22}\)
According to mole concept:
\(6.022\times 10^{23}\) number of molecules are present in 1 mole of a compound
So, \(3.55\times 10^{22}\) number of molecules will be present in = \(\frac{1}{6.022\times 10^{23}}\times 3.55\times 10^{22}=0.059moles\) of water.
To calculate the mass of a substance, we use the equation:
\(\text{Number of moles}=\frac{Given mass}}{\text{Molar mass}}\)
Molar mass of water = 18 g/mol
Moles of water = 0.059 moles
Putting values in above equation, we get:
\(0.059mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=1.062g\)
Hence, the mass of water sample is 1.062 grams