the radius of a palladium atom is 137 pm. how many palladium atoms would have to be laid side by side to span a distance of 4.25 mm?
Answer:
\(1.551\times 10^7\) atoms of palladium are to be laid side by side to span a distance of 4.25 mm.
Explanation:
The radius of the palladium atom, r = 137 pm
Diameter of the palladium atom = 2r = 137 pm = 274 pm
Let the number of palladium atoms laid side by side be x
Length of the chain = 4.25 mm = \(4.25\times 10^9 pm\)
\(1 mm = 10^9 pm\)
\(x\times 274 pm =4.25\times 10^9 pm\)
\(x=\frac{4.25\times 10^9 pm}{274 pm}=1.551\times 10^7\)
\(1.551\times 10^7\) atoms of palladium are to be laid side by side to span a distance of 4.25 mm.