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the radius of a palladium atom is 137 pm. how many palladium atoms would have to be laid side by side to span a distance of 4.25 mm?

Verified Answer :

jwillm

4.25mm / 137pm = 31 021 897.8

Answer:

\(1.551\times 10^7\) atoms of palladium are to be laid side by side to span a distance of  4.25 mm.

Explanation:

The radius of the palladium atom, r = 137 pm

Diameter of the palladium atom = 2r =  137 pm = 274 pm

Let the number of palladium atoms laid side by side be x

Length of the chain = 4.25 mm = \(4.25\times 10^9 pm\)

\(1 mm = 10^9 pm\)

\(x\times 274 pm =4.25\times 10^9 pm\)

\(x=\frac{4.25\times 10^9 pm}{274 pm}=1.551\times 10^7\)

\(1.551\times 10^7\) atoms of palladium are to be laid side by side to span a distance of  4.25 mm.