Answer:
244 moles of phosphorus are present in 61.0 moles of \(P_4O_{10}\).
Explanation:
Moles of \(P_4O_{10}\) = 61.0 moles
1 mol of \(P_4O_{10}\) contains 4 moles of phosphorus.
Then 61.0 moles of \(P_4O_{10}\) will contain:
\(61.0 mol\times 4=244 mol\) of phosphorus
244 moles of phosphorus are present in 61.0 moles of \(P_4O_{10}\).
