Answer:
Distance covered by the car, s = 21.56 meters
Explanation:
Given that,
Initially, the car is at rest, u = 0
It reaches a speed, final speed, v = 6.6 m/s
Time, t = 6.5 s
We need to find the distance covered by the car during this time. Firstly, we can find the acceleration of the car using equation of motion as :
\(v=u+at\)
\(6.6=0+a\times 6.5\)
\(a=1.01\ m/s^2\)
Now using third equation of motion to find distance (s) as :
\(s=\dfrac{v^2-u^2}{2a}\)
\(s=\dfrac{(6.6)^2}{2\times 1.01}\)
s = 21.56 meters
So, the distance traveled by the car during 6.5 seconds is 21.56 meters. Hence, this is the required solution.
