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The length of a rectangle is one unit shorter than one-sixth of the width, x.


Enter an expression in the box that represents the perimeter of the rectangle.


Note: Use one variable and a fraction in the answer.

Verified Answer :

texaschic101

P = 2(L + W)

L = 1/6W - 1

P = 2(1/6W - 1 + W)
P = 2(7/6W - 1)
P = 7/3W - 2......oh, w is supposed to be x....7/3x - 2....I know u want a variable and a fraction...but I got a constant in there

calculista

Let

y--------> the length of the rectangle

x--------> the width of the rectangle

we know that

The perimeter of the rectangle is equal to

\(P=2x+2y\) -------> equation \(1\)

\(y=\frac{1}{6}x-1\) --------> equation \(2\)

Substitute equation \(2\) in equation \(1\)

\(P=2x+2*[\frac{1}{6}x-1]\\ \\P=2x+\frac{2}{6}x-2\\ \\P=\frac{14}{6}x-2\\ \\P=(\frac{7}{3}x-2)\ units\)

therefore

the answer is

the perimeter of the rectangle is

\(P=(\frac{7}{3}x-2)\ units\)

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