A person weighing 800 newtons travels to another planet with twice the mass and twice the radius of earth. what is the person's weight on the new plant?

F=m1m2G/r2. m1 anf m2 are the masses. G is the universal gravitation constant (=6.67310^-11). R is distance between m1 and m2. So the earth's mass is 5.9810^24 kg, m1, person is 800/ 9.81=81.55 kg. Now all we have to do is film in: F= 6.67310^-1181.55 kg (5.9810^24 2kg)/ (6.3810^6*2)^2= 399.73 N. You may recalculate, maybe I forgot something, but the formula is right.

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nishantwork777 nishantwork777 · Answer 2 · 2021-12-29T03:36:43-05:00

The weight of the person on the new planet is 400 N.

Given information:

The weight of a person on the earth is \(w=800\) N.

To find out the weight we need to know the acceleration due to gravity of the planet, and as we know acceleration due to gravity for earth is

\(g=\dfrac{Gm}{r^2}\)

The mass of new planet is 2 times that of earth and the size is double.

The value of gravity for the new planet will be,

\(g'=\dfrac{G\times 2m}{(2r)^2}\\g'=\dfrac{Gm}{2r^2}\\g'=\dfrac{g}{2}\)

So, the weight of the person on the new planet will be,

\(w'=mg'\\w'=m\dfrac{g}{2}\\w'=\dfrac{w}{2}\\w'=\dfrac{800}{2}\\w'=400\rm\;N\)

Therefore, the weight of the person on the new planet is 400 N.

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https://brainly.com/question/14767944