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emilykane1993
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Suppose a population is carrying a condition controlled by two alleles: R (dominant) and r (recessive). If the frequency of the r allele is 15%, and the frequency of the R allele is 85%, what will be the frequency of the RR genotype, assuming evolution is not occurring?



A25.5 percent
B72.25 percent
C12.75 percent
D2.25 percent

Verified Answer :

Putpin101

B.) 72.25 percent.

Hopefully this helps! =^ ^=

smilodon

Since no evolution is happening we can use the Hardy-Weinberg equation to solve this problem. This equation enables us to calculate the frequency of a genotype from the frequencies of the alleles.

\(R^{2}\) the frequency of the dominant homozygote

2Rr the frequency of the heterozygote

\(r^{2}\) the frequency of the recessive homozygote

Therefore, the frequency of the RR genotype is R\(^{2}\) = 0,85[tex] ^{2} which is 0,72.

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