A soccer player is running upfield at 10m/s and comes to a stop in 3 seconds facing the same direction. What is his acceleration
-10/3m/s2. The formula for acceleration is (Final speed - initial speed)/ time.
Thus, (0m/s - 10m/s)/3s is 10m/s/3s which then can be simplified to /10/3m/s2
Answer:
The acceleration is 3.33 m/s².
Explanation:
Given that,
Velocity = 10 m/s
Time t = 3 sec
We need to calculate the acceleration
Using equation of motion
\(v=u+at\)
Where, v = final velocity
u = initial velocity
t = time
a = acceleration
Put the value into the formula
\(10=0+a\times3\)
\(a=\dfrac{10}{3}\)
\(a=3.33\ m/s^2\)
Hence, The acceleration is 3.33 m/s².