Answer:
The first four terms of a GP are, {40, 20, 10, 5}.
Step-by-step explanation:
The nth term of a geometric progression is: \(T_{n}=a_{1}\times r^{n-1}\)
Here a₁ = first term and r = common ratio.
Given: a₁ = 40 and r = 0.50
The 1st term is,
\(T_{1}=a_{1}\times r^{1-1}=a_{1}=40\)
The 2nd terms is,
\(T_{2}=a_{1}\times r^{2-1}=a_{1}=40\times (0.50)^{1}=20\)
The 3rd term is,
\(T_{3}=a_{1}\times r^{3-1}=a_{1}=40\times (0.50)^{2}=10\)
The 4th term is,
\(T_{4}=a_{1}\times r^{4-1}=a_{1}=40\times (0.50)^{3}=5\)
Thus, the first four terms of a GP are, {40, 20, 10, 5}.
