Ben works part time in a warehouse . His boss is going to send one employee home early . Of his 56 employees 21 are part time . If the boss picks one employee at random what are the chances it will be a part time emplyee sent home ?
21/56 which reduces to 3/8 ...or if u need a percent, it is 37.5%
Boss has 56 (number of possible outcomes) employees, 21 (number of favorable outcomes) of them are part time.
Use the theoretical probability:
\(Pr(\text{selected employee is a part time emplyee})=\dfrac{\text{number of favorable outcomes}}{\text{number of possible outcomes}} =\dfrac{21}{56}=\dfrac{3}{8} =0.375.\)
In percent it is 37.5%.
Answer: 0.375.