The answer is d. 5y − x = −10. 3y − x = 24
\(\frac{1}{5}x-2= \frac{1}{3}x+8=y\)
⇒ \(y= \frac{1}{5}x-2\)
\(y= \frac{1}{3}x+8\)
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\(y= \frac{x}{5} -2= \frac{x}{5} - \frac{10}{5} = \frac{x-10}{5}\)
\(y= \frac{x}{3} +8= \frac{x}{3} + \frac{24}{3} = \frac{x+24}{3}\)
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\(y= \frac{x-10}{5}\) ⇒ \(5y=x-10\)
\(y= \frac{x+24}{3}\) ⇒ \(3y=x+24\)
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\(5y-x=-10\)
\(3y-x=24\)
