The lateral area of a frustum of a regular triangular pyramid is 1,081cm^2, and the altitude and lateral edges are 24cm and 26cm, respectively. Find the lengths of the sides of the bases.
Lateral Area = 3 ( a + b ) /2 24 1,081 = 36 * ( a + b ) /:36 a + b ≈ 30 (( a - b ) /2)² = 26 ² - 24² = 676 - 576 = 100 ( a - b ) / 2 = 10 a - b = 20 a = b + 20 a + b = 30 2 b + 20 = 30 2 b = 10 b = 10 :2 b = 5 cm a = 5 + 20 a = 25 cm
