By definition, we have to:
\(E = IZ
\)
Where,
E: voltage
I: current
Z: Resistance
To calculate the voltage value, we must replace the following values in the given equation:
\(I = 3 + 2i
Z = 2 - i
\)
We have then:
\(E = (3 + 2i) (2 - i)
\)
Making the product of complex numbers we have:
\(E = (3 * 2 - 3i) + (4i - 2i ^ 2)
E = (6 - 3i) + (4i - 2 (-1))
E = (6 - 3i) + (4i +2)
\)
\(E = (6 + 2) + (4-3) i
E = 8 + i
\)
Answer:
the voltage of the circuit is:
\(E = 8 + i
\)
option C
