jkayiskybFlak
Answered

Israel started to solve a radical equation in this way:

Square root of x plus 6 − 4 = x

Square root of x plus 6 − 4 + 4 = x + 4

Square root of x plus 6 = x + 4

(Square root of x plus 6)2 = (x + 4)2

x + 6 = x2 + 8x + 16

x + 6 − 6 = x2 + 8x + 16 − 6

x = x2 + 8x + 10

x − x = x2 + 8x + 10 – x

0 = x2 + 7x + 10

0 = (x + 2)(x + 5)



x + 2 = 0 x + 5 = 0

x + 2 − 2 = 0 − 2 x + 5 − 5 = 0 – 5

x = −2 x = −5


Solutions = −2, -5



What mistake did isreal make?

AHe subtracted 6 before subtracting x. B) He added 4 before squaring both sides. C) He factored x2 + 7x + 10 incorrectly. D) He did not check for extraneous solutions.

Verified Answer :

HomertheGenius

Only x = - 2 works in the original equation. 
√(-2 + 6 ) - 4 = - 2
√2  - 4 = -2
- 2 = - 2
and: √(- 5 + 6 ) - 4 = - 5
√ 1 - 4 = - 5
- 3 ≠ - 5 ( x = - 5  does not work ).
Answer: D ) He did not check for extraneous solutions.

taskmasters

I think the correct answer from the choices listed above is option D. The mistake that he did was that he did not check extraneous solutions.

√(-2 + 6 ) - 4 = - 2
√2  - 4 = -2
- 2 = - 2
and: √(- 5 + 6 ) - 4 = - 5
√ 1 - 4 = - 5
- 3 ≠ - 5

Therefore, x = - 5  does not work.