Answer:
Step-by-step explanation:
The vertical motion of the object is defined by using the height function h(t) such that :
h(t) = -16t² + vt + s , where t is the time instant , v is the initial velocity and s is the initial height of the object.
Now, the height of the bridge = 200 feet
So it would be the initial height ⇒ s = 200
Initially the speed is 0 because the body is in rest at time instant 0 sec.
Hence, the resultant equation is : h(t) = -16t² + 200
And the graph is attached below :
