When solutions containing silver ions and chloride ions are mixed, silver chloride precipitates: Ag+(aq)+Cl−(aq)→AgCl(s)ΔH=−65.5kJ. Calculate ΔH for formation of 0.490mol of AgCl by this reaction.
Arrhenius acid is acid which gives the H+ and arhenius base is one which donates the -OH group thats why it can identify
Answer:
The ΔH for the formation of 0.490 mol of AgCl is - 32.095 kJ.
Explanation:
Ag⁺(aq)+Cl⁻(aq)→ AgCl(s) ΔH=−65.5kJ
We need to consider that the value of ΔH given is for each mol of AgCl formed.
1 mol AgCl ________________ - 65.5 kJ
0.490 mol AgCl ____________ x
x = - 32.095 kJ