area = 20 meters square
perimeter = 24 meters
lw=20
2l+2w=24 divide both sides by 2 and will get
l+w=12 => l = 12-w substitute inside the first equation of area
(12-w)w = 20
12w -w^2 =20
w^2 -12w +20 = 0
D = 144 -4*20 = 144-80 = 64
w_1,2 = (12 +/- 8)/2 = 20/2 = 10 and 4/2 = 2
l = 12 -w
l_1 = 12 - 10 = 2
l_2 = 12 - 2 = 10
so from these result that the length of the rectangle equal 10 and the width of the rectangle equal 2
hope helped
