2x^{2} +4x+1=0 Solve for x.
2x^2 + 4x + 1 = 0 2x^2 + 4x + 1 - 1 = 0 - 1 2x^2 + 4x = -1 X(2x + 4) = -1 X = -1. 2x + 4 = -1 2x + 4 - 4 = -1 - 4 2x = -52x/2 = -5/2X = -5/2. I believe these are the solutions. If not you can use the quadratic formula to solve for the roots, solutions.
