1/9 divided by 15/13
\(\frac{\frac{1}{9}}{\frac{15}{13}}=\ \ \ \ \ \ | multiply\ first\ fraction\ by\ inverse\ of\ the\ second\\\\ \frac{1}{9}*\frac{13}{15}=\frac{13}{9*15}=\frac{13}{135}\\\\Solution\ is\ \frac{13}{135}.\)
\(\frac{1}{9}\)÷\(\frac{15}{13}\)=\(\frac{1}{9}\)×\(\frac{13}{15}\) because when dividing fractions, you flip-flop the second fraction and then multiply both. \(\frac{1}{9}\)×\(\frac{13}{15}\)=\(\frac{13}{135}\)Your answer is \(\frac{13}{135}\)
