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Verified Answer :

Cam943

Let the smallest number equal n. Therefore, the other numbers are (n+2) and (n+4).

The sum of the three numbers are:

\(n + (n+2) + (n+4)\)

\(=3n+6\)

Since the sum equals 78, 

\(3n+6=78\)

Divide both sides by 3, 

\(n+2=26\)

\(n=24\)

Therefore, the smallest number is 24. 


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