How many atoms are in 0.750 moles of zinc?
(doesn't really matter that it's zinc :) )It is \(0.75*N_A\), where \(N_A=6.023*10^{23}\) (in some books 6.022).
4.52 X 10²³ atoms Use Avogadro's number to multiply 0.750 moles times 6.022 X 10²³ atoms. Then divide by 1 atom to get the answer. hope that helped