\(169 = s^{2}\)
Square-rooting on both sides, we get,
\(\sqrt{169 } = (+-)\sqrt{ s^{2} }\)
\(\sqrt{13*13 } = (+-)\sqrt{ s^{2} }\)
\(\sqrt{ 13^{2} } =(+-)\sqrt{ s^{2} }\)
Since, the square cancels out square- square root sign, we have
\(13 = (+-)s\)
\((+-)s = 13\)
So, when "s" is positive, the value of "s" is 13
and when "s" is negative, the value of "s" is -13
So, the values of "s" are 13 , -13
