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Rere1611 Rere1611
  • 11-10-2014
  • Mathematics
Answered

What is 2x (to the second power)y (to the fourth power ) times 4x (squared) y (to the fourth power) times 3x over 3x (negative third power) y(squared)

Verified Answer :

mariamikayla
mariamikayla mariamikayla
  • 11-10-2014

\(2x^2y^4*4x^2y^4*\frac{3xy^2}{3x^{-3}}= 8x^4y^8* \frac{3xy^2}{1}*\frac{3x^3}{1}= \\\\ =8x^4y^8*9x^4y^2= \\\\ =\boxed{72x^8y^{10}}\)

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