Verified Answer :

caylus

Hello,

y'=\(( \sqrt{3x+ \sqrt{3x+ \sqrt{3x} } } )'\)

\(y'=\dfrac{(3+\frac{1}{2\sqrt{3x+\sqrt{3x}}})*(3+\frac{3}{2\sqrt{3x}})}{2( \sqrt{3x+ \sqrt{3x+ \sqrt{3x} } } )}\)

This make me think of a Ramanuyan 's formula of (x+1)