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Ne1dRoraceymccrose
Ne1dRoraceymccrose Ne1dRoraceymccrose
  • 17-06-2016
  • Mathematics
Answered

What is the product?


(6r − 1)(−8r − 3)


−48r2 − 10r + 3

−48r2 − 10r − 3

−48r2 + 3

−48r2 − 3

Verified Answer :

nobillionaireNobley
nobillionaireNobley nobillionaireNobley
  • 17-06-2016

\((6r-1)(-8r-3)=6r(-8r-3)-1(-8r-3) \\ =-48 r^{2} -18r+8r+3 \\ =-48 r^{2} -10r+3\)

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