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If sin Θ = 5 over 6 , what are the values of cos Θ and tan Θ? (2 points)




cos Θ = ± 11 over 36 ; tan Θ = ± 1 over 11

cos Θ = ± square root 11 over 6 ; tan Θ = negative 1 over 11

cos Θ = ± 11 over 6 ; tan Θ = 11 over 6

cos Θ = ± square root 11 over 6 ; tan Θ = ± 5 square root 11 over 11

Verified Answer :

HomertheGenius

cos² (theta) = 1 - (5/6)²
cos² (theta) = 1 - 25/36 = 11/36
cos(theta) = \(\sqrt{ \frac{11}{36} }=\pm \frac{ \sqrt{11} }{6}\)
tan(theta) = sin(theta) / cos (theta)=\(\pm\frac{5/6}{ \sqrt{11}/6 }= \pm \frac{5}{ \sqrt{11} } =\pm \frac{5 \sqrt{11} }{11}\)
Answer: D)

Amaya6295

Answer:

cosΘ=±\(\frac{\sqrt{11} }{6}\)

tanΘ =±\(\frac{5\sqrt{11} }{11}\)

Step-by-step explanation:

I took the test and got it right

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