Answer:
\((f+g)(x)= \sqrt{3x+7} + \sqrt{3x-7}\)
Step-by-step explanation:
\(f(x)= \sqrt{3x+7}\)
\(g(x)= \sqrt{3x-7}\)
we need to find (f+g)(x)
(f+g)(x)= f(x) + g(x)
replace f(x) and g(x) expressions
(f+g)(x)= f(x) + g(x)= \(\sqrt{3x+7} + \sqrt{3x-7}\)
both square root have different terms inside the root
so we cannot add square root terms.
\((f+g)(x)= \sqrt{3x+7} + \sqrt{3x-7}\)
