a^3-b^3/a^3b^3+a^2b^4+ab^5
Hello,If the question is to simplify then\(\dfrac{ a^{3}-b^{3}}{a^{3}b^{3}+a^{2}b^{4}+ab^{5}}\)\(=\dfrac{ (a-b)(a^{2}+ab+b^{2})}{ab^{3}(a^{2}+ab+b^{2})}\)\(=\dfrac{ a-b}{ab^{3}}\)
