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Find the area of the regular polygon. Give the answer to the nearest tenth.


pentagon with a side of 6 m (1 point)

A123.9 m²
B12.4 m²
C61.9 m²
D49.5 m²

Verified Answer :

The area of the regular pentagon:\(A=5* \frac{s*a}{2}\) where s=6m, and a=3tg 54°= 31.37=4.13 m
Explanation: 54° is a half of the inner angle of the pentagon. The interior angles of a pentagon add up to 540°. Each angle is 108°.
Finally: A=\(5* \frac{6*4.13}{2}\)=61.93 m².
Answer: C) 61.9 m²

Answer:

61.9

Step-by-step explanation:

center center is 72 degree for each triangle

the distance of center to the side h=3/tan 36=4.12,

area=5 (4.126)/2=61.94==61.9