At a temperature of 280k, the gas in a cylinder has a volume of 20.0 liters.


If the volume of the gas is decreased to 10.0 liters, what must the temperature be for the gas to remain at a constant pressure?

Verified Answer :

Temperature should be 140k to maintain constant pressure

Answer:

T = 140 K

Explanation:

As we know by ideal gas law

\(PV = nRT\)

now if pressure of the gas is constant

then we will have

\(V = \frac{nR}{P} T\)

now we have

\(V_1 = 20.0 litre\)

\(T_1 = 280 K\)

\(V_2 = 10.0 litre\)

now from above equation

\(\frac{20.0}{10.0} = \frac{280}{T}\)

\(T = 140 K\)