A gas has an initial volume of 24.6 L at a pressure of 1.90 atm and a temperature of 335 K. The pressure of the gas increases to 3.50 atm, and the volume of the gas increases to 31.3 L.
The problem can be solved by using the formula associated with the gas laws. It is as follows:
PV/T
Given:
P1 = 1.9 atm
V1 = 24.6 L
T1 = 335 K
P2 = 3.5 atm
V2 = 31.3 L
T2 = ?
Substituting the given:
P1V1/T1 = P2V2/T2
(1.9 24.6)/335 = (3.5 31.3)/T2
T2 = 785.18 K