If the value of sinx=0.42, what is cos x?
from the relation of sin(x)^2 + cos(x)^2 = 1 (0.42)^2 + cos(x)^2 = 1 cos(x)^2 = 1 - (0.42)^2 cos(x) = √(1-(0.42)^2)cos(x) = 0.9075
