Answer:
\((x-1)(x-(\frac{-1-i\sqrt{3}}{2}))(x+(\frac{-1+i\sqrt{3}}{2}))\)
Step-by-step explanation:
Given equation : \(f(x)=x^3-1\)
To write it's factored form :
⇒ \(x^3-1=0\)
⇒\((x-1)(x^2+x+1)\)
⇒\((x-1)(x-(\frac{-1-i\sqrt{3}}{2}))(x+(\frac{-1+i\sqrt{3}}{2}))\)
⇒\(x=1,x=\frac{-1-i\sqrt{3}}{2}),x=\frac{-1+i\sqrt{3}}{2}\)
⇒\(x=1,\frac{-1-i\sqrt{3}}{2},\frac{-1+i\sqrt{3}}{2}\)
