gomezlaura227 gomezlaura227

09-06-2016
Chemistry

Answered

How many moles of I2 will form 3.58 g of NI3?

Verified Answer :

taskmasters taskmasters

11-06-2016

1.
The balanced chemical reaction is:

N2 +3 I2 = 2NI3

We are given the amount of product formed.
This will be the starting point of our calculations.

3.58 g NI3 ( 1 mol NI3 / 394.71 g NI3 ) ( 3
mol I2 / 2 mol NI3 ) = 0.014 mol I2.

Thus, 0.014 mol of I2 is needed to form the
given amount of NI3.

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