Answer:
\(4(x-7)^2-(x-7)+3\)
Step-by-step explanation:
Given the functions:
\(s(x)=x-7\) and \(t(x)=4x^2-x+3\)
We have to find the \((t \circ s)(x)\)
\((t \circ s)(x) = t(s(x))\)
Substitute the function s(x) we have;
⇒\(t(s(x)) = t(x-7)\)
Replace x with x-7 in t(x) we have;
⇒\(t(x-7) = 4(x-7)^2-(x-7)+3\)
⇒\((t \circ s)(x) = 4(x-7)^2-(x-7)+3\)
Therefore, the expression which is equivalent to \((t \circ s)(x)\) is:
\(4(x-7)^2-(x-7)+3\)
