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suppose that you look into a photometer's eyepiece and the fluorescent disks appear to be equal in intensity. If the distance between the photometer to lamp 1 is 400mm, the distance between the photometer to lamp 2 is 200 mm, and the intensity of lamp 2 is known to be 15 candelas, what is the intensity to lamp 1?

Verified Answer :

Use the Inverse square law, Intensity (I) of a light is inversely proportional to the square of the distance(d).

I=1/(dd)

Let Intensity for lamp 1 is L1 distance be D1 so on, L2 D2 for Intensity for lamp 2 and its distance.

L1/L2=(D2D2)/(D1D1)

L1/15=(200200)/(400400)
L1=150.25
L1=3.75 candela

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