If the force (at 90 degree to the lever arm) applied is 15 N and it's applied at 2.0 m from the pivot point (point of rotation), what is the torque on the lever?
The formula to calculating the torque is this: τ = r F sinθ where τ is the torque r is the distance from the pivot point θ is the angle from the lever arm where the force is applied
Plugging in the values: τ = 2.0 m (15N) sin 90 τ = 30 N m
