Verified Answer :

caylus

Hello,

If x≠1 and x≠-1 then

\(\dfrac{3x-3}{x^2-1}*\dfrac{(x+2)(x+1)}{x-1}=\dfrac{3(x-1)}{x-1}*\dfrac{(x+2)(x+1)}{(x-1)(x+1)}\\=\dfrac{3(x+2)}{x+1}\)




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