Given:
128g sample of
water
2808J of heat
energy
Required:
Change in
temperature
Solution:
This can be solved
through the equation H = mCpT
where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.
The specific heat
of the water is 4.18 J/g-K
Plugging in the
values into the equation
H = mCpT
2808J = (128g)
(4.18 J/g-K) T
T
= 5.25 K
