Explanation :
The resistance of the flashlight is 2.4 ohms
The current flowing in the circuit is 2.5 A
The Ohm's law gives the relation between the following quantities i.e.
Current
voltage
and resistance
Mathematically, Ohm's law can be written as :
V =I R
\(V=2.5\ A\times 2.4\ \Omega\)
\(V=6\ Volts\)
The voltage applied by the batteries is 6 volts.
Hence, this is the required solution.
