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Answered

Choose the equation that could be used to find three consecutive integers whose sum is 36.


n + (n + 2) + (n + 4) = 36


n + (n + 1) + (n + 3) = 36


n + (n + 1) + (n + 2) = 36


n + (n − 1) + (n − 3) = 36

Verified Answer :

n +(n+1) + ( n+2)=36
the third answer

calculista

Let

n--------> the first integer

n+1------> the second consecutive integer

n+2-----> the third consecutive integer

we know that

\(n+(n+1)+(n+2)=36\\3n+3=36\\3n=36-3\\3n=33\ =33/3\ =11\)

the numbers are

\(11,12,13\)

therefore

the answer is

The equation is \(n+(n+1)+(n+2)=36\)

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