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garydesir1
garydesir1
23-05-2016
Mathematics
Answered
Please, show your work . Thanks
Verified Answer :
apologiabiology
apologiabiology
23-05-2016
seems to be a geometric sequence
common ratio is -4
first erm is -2
\(a_{n}=-2(-4)^{n-1}\)
5. x=-1
remember x^-1=1/x
f(-1)=4(7^-1)=4(1/7)=4/7
f(2)=4(7^2)=4(49)=196
6. remember
(ab)/(cd)=(a/c)(b/d)
also
(x^m)/(x^n)=x^(m-n)
and
(x^m)(x^n)=x^(m+n)
so
\(\frac{4.5*10^{3}}{9*10^{7}}\)
=
(
\(\frac{4.5}{9}\)
)(
\(\frac{10^{3}}{10^{7}}\)
)=
(0.5)(
\(10^{3-7}\)
=
(0.5)(10^-4)=
(5)(10^-1)(10^-4)=
(5)(10^(-1-4)
5*10^-5
4.
\(a_{n}=-2(-4)^{n-1}\)
5. f(-1)=4/7
f(2)196
6. 5 times 10^-5
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